mohon bantuannya kak
FUngsi Kuadrat
Penjelasan dengan langkah-langkah:
f(x)= 2x² + 3x + 2
a= 2, b = 3, c = 2
a. Nilai y , jika x = 5
y= 2.5² + 3(5) + 2
y = 2(25) + 15 + 2
y = 50 + 17
y = 67
b. persamaan sumbu simetri
x = -b/2a
x = -3/(2)(2)
x = - 3/4
c. titik balik (xp,yp)
xp= - b/2a = -3/4
yp = D/-4a
yp = (b² -4ac) / -4a
yp = ( (-3)²- 4(2)(2)) / -4(2)
yp = (9 -16)/(-8)
yp= - 7/-8
yp= 7/8
titik balik = (-3/4 , 7/8)
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